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Popular Calculus >

integral of y+1

Solution

\int y + 1 d y

Solution

\frac{y ^{2}}{2} + y + C

Solution steps

\int y + 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int y d y + \int 1 d y

\int y d y = \frac{y ^{2}}{2}

\int 1 d y = y

= \frac{y ^{2}}{2} + y

Add a constant to the solution

= \frac{y ^{2}}{2} + y + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of y+1 ?
The integral of y+1 is (y^2)/2+y+C