What is the tangent of f(x)=0.6831x^{-1.031},\at x=1 ?

The tangent of f(x)=0.6831x^{-1.031},\at x=1 is y=-0.7042761x+1.3873761

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tangent of f(x)=0.6831x^{-1.031},\at x=1

tangent of

f (x) = 0.6831 x^{- 1.031}, at x = 1

y = - 0.7042761 x + 1.3873761

Solution steps

Find the tangent point:

(1, 0.6831)

Find the slope of

f (x) = 0.6831 x^{- 1.031} : \frac{df ( x )}{d x} = - \frac{0.7042761}{x ^{2.031}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 0.7042761

Find the line with slope m=

- 0.7042761

and passing through

(1, 0.6831) : y = - 0.7042761 x + 1.3873761

y = - 0.7042761 x + 1.3873761

What is the tangent of f(x)=0.6831x^{-1.031},\at x=1 ?
The tangent of f(x)=0.6831x^{-1.031},\at x=1 is y=-0.7042761x+1.3873761