What is the integral of 4csc(x)cot(x) ?

The integral of 4csc(x)cot(x) is -4csc(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 4csc(x)cot(x)

\int 4 csc (x) cot (x) d x

- 4 csc (x) + C

Solution steps

\int 4 csc (x) cot (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int csc (x) cot (x) d x

Apply u-substitution

= 4 \cdot \int - 1 d u

Integral of a constant:

\int a d x = a x

= 4 (- 1) u

Substitute back

u = csc (x)

= 4 (- 1) csc (x)

Simplify

= - 4 csc (x)

Add a constant to the solution

= - 4 csc (x) + C

What is the integral of 4csc(x)cot(x) ?
The integral of 4csc(x)cot(x) is -4csc(x)+C