What is the derivative of 8e^x+x ?

The derivative of 8e^x+x is 8e^x+1

What is the first derivative of 8e^x+x ?

The first derivative of 8e^x+x is 8e^x+1

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derivative of

8 e^{x} + x

8 e^{x} + 1

Solution steps

\frac{d}{d x} (8 e^{x} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 e^{x}) + \frac{d x}{d x}

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

\frac{d x}{d x} = 1

= 8 e^{x} + 1

What is the derivative of 8e^x+x ?
The derivative of 8e^x+x is 8e^x+1
What is the first derivative of 8e^x+x ?
The first derivative of 8e^x+x is 8e^x+1