What is the d/(dt)(-4.9t^2+24.5t+6.8) ?

The d/(dt)(-4.9t^2+24.5t+6.8) is -9.8t+24.5

What is the first d/(dt)(-4.9t^2+24.5t+6.8) ?

The first d/(dt)(-4.9t^2+24.5t+6.8) is -9.8t+24.5

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\frac{d}{d t} (- 4.9 t^{2} + 24.5 t + 6.8)

- 9.8 t + 24.5

Solution steps

\frac{d}{d t} (- 4.9 t^{2} + 24.5 t + 6.8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (4.9 t^{2}) + \frac{d}{d t} (24.5 t) + \frac{d}{d t} (6.8)

\frac{d}{d t} (4.9 t^{2}) = 9.8 t

\frac{d}{d t} (24.5 t) = 24.5

\frac{d}{d t} (6.8) = 0

= - 9.8 t + 24.5 + 0

Simplify

= - 9.8 t + 24.5

What is the d/(dt)(-4.9t^2+24.5t+6.8) ?
The d/(dt)(-4.9t^2+24.5t+6.8) is -9.8t+24.5
What is the first d/(dt)(-4.9t^2+24.5t+6.8) ?
The first d/(dt)(-4.9t^2+24.5t+6.8) is -9.8t+24.5