What is the solution for xy^'-2y=-2x^2+x+1 ?

The solution for xy^'-2y=-2x^2+x+1 is y=-2x^2ln(x)-x-1/2+c_{1}x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

xy^'-2y=-2x^2+x+1

x y^{^{'}} - 2 y = - 2 x^{2} + x + 1

y = - 2 x^{2} ln (x) - x - \frac{1}{2} + c_{1} x^{2}

Solution steps

x y^{'} (x) - 2 y = - 2 x^{2} + x + 1

Solve linear ODE:

y = - 2 x^{2} ln (x) - x - \frac{1}{2} + c_{1} x^{2}

y = - 2 x^{2} ln (x) - x - \frac{1}{2} + c_{1} x^{2}

What is the solution for xy^'-2y=-2x^2+x+1 ?
The solution for xy^'-2y=-2x^2+x+1 is y=-2x^2ln(x)-x-1/2+c_{1}x^2