What is the derivative of (a+bx^2/(x^2)) ?

The derivative of (a+bx^2/(x^2)) is -(2a)/(x^3)

What is the first derivative of (a+bx^2/(x^2)) ?

The first derivative of (a+bx^2/(x^2)) is -(2a)/(x^3)

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\frac{d}{d x} (\frac{a + b x ^{2}}{x ^{2}})

- \frac{2 a}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{a + b x ^{2}}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( a + b x ^{2} ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( a + b x ^{2} )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (a + b x^{2}) = 2 b x

\frac{d}{d x} (x^{2}) = 2 x

= \frac{2 b x x ^{2} - 2 x ( a + b x ^{2} )}{( x ^{2} ) ^{2}}

Simplify

\frac{2 b x x ^{2} - 2 x ( a + b x ^{2} )}{( x ^{2} ) ^{2}} : - \frac{2 a}{x ^{3}}

= - \frac{2 a}{x ^{3}}

What is the derivative of (a+bx^2/(x^2)) ?
The derivative of (a+bx^2/(x^2)) is -(2a)/(x^3)
What is the first derivative of (a+bx^2/(x^2)) ?
The first derivative of (a+bx^2/(x^2)) is -(2a)/(x^3)