y^{''}+4y^'=0

Lösung

y^{^{''}} + 4 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- 4 t}

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 t}

y = c_{1} + c_{2} e^{- 4 t}

\frac{\partial}{\partial y} (x z^{2})

\frac{d ^{3}}{d x ^{3}} (\frac{4}{x ^{2}})

\int_{- 1}^{2} (y + 2 - y^{2}) d y

in v erse l a pl a ce \frac{e ^{\frac{- π}{2}}}{s ^{2} + 9}

\frac{\partial}{\partial x} (x^{3} + x^{2} y - 4 y^{3})