What is the derivative of sqrt(8+x) ?

The derivative of sqrt(8+x) is 1/(2sqrt(8+x))

What is the first derivative of sqrt(8+x) ?

The first derivative of sqrt(8+x) is 1/(2sqrt(8+x))

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\frac{d}{d x} (8 + x)

\frac{1}{2 8 + x}

Solution steps

\frac{d}{d x} (8 + x)

Apply the chain rule:

\frac{1}{2 8 + x} \frac{d}{d x} (8 + x)

= \frac{1}{2 8 + x} \frac{d}{d x} (8 + x)

\frac{d}{d x} (8 + x) = 1

= \frac{1}{2 8 + x} \cdot 1

Simplify

= \frac{1}{2 8 + x}

What is the derivative of sqrt(8+x) ?
The derivative of sqrt(8+x) is 1/(2sqrt(8+x))
What is the first derivative of sqrt(8+x) ?
The first derivative of sqrt(8+x) is 1/(2sqrt(8+x))