y^{''}-y^'+30y=0

Lösung

y^{^{''}} - y^{^{'}} + 30 y = 0

y = e^{\frac{t}{2}} (c_{1} cos (\frac{119 t}{2}) + c_{2} sin (\frac{119 t}{2}))

Schritte zur Lösung

y^{''} (t) - y^{'} (t) + 30 y = 0

Solve linear ODE:

y = e^{\frac{t}{2}} (c_{1} cos (\frac{119 t}{2}) + c_{2} sin (\frac{119 t}{2}))

y = e^{\frac{t}{2}} (c_{1} cos (\frac{119 t}{2}) + c_{2} sin (\frac{119 t}{2}))

l a pl a ce t r an s f or m 3 sin (2 t) - 3 cos (2 t)

\frac{d}{d x} (x^{y} - y^{x})

y^{^{'}} - y = x^{2}

x \to 7 lim (3 x - 5)

x \to 0 lim (\frac{2 x ^{2} + 5 x + 7}{x})