What is the derivative of 1/x-3sin(x) ?

The derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)

What is the first derivative of 1/x-3sin(x) ?

The first derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)

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\frac{d}{d x} (\frac{1}{x} - 3 sin (x))

- \frac{1}{x ^{2}} - 3 cos (x)

Solution steps

\frac{d}{d x} (\frac{1}{x} - 3 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) - \frac{d}{d x} (3 sin (x))

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

= - \frac{1}{x ^{2}} - 3 cos (x)

What is the derivative of 1/x-3sin(x) ?
The derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)
What is the first derivative of 1/x-3sin(x) ?
The first derivative of 1/x-3sin(x) is -1/(x^2)-3cos(x)