What is the solution for y^'=-3y+e^{-2x} ?

The solution for y^'=-3y+e^{-2x} is y= 1/(e^{2x)}+(c_{1})/(e^{3x)}

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y^'=-3y+e^{-2x}

y^{^{'}} = - 3 y + e^{- 2 x}

y = \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{3 x}}

Solution steps

y^{'} (x) = - 3 y + e^{- 2 x}

Solve linear ODE:

y = \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{3 x}}

y = \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{3 x}}

What is the solution for y^'=-3y+e^{-2x} ?
The solution for y^'=-3y+e^{-2x} is y= 1/(e^{2x)}+(c_{1})/(e^{3x)}