What is the solution for -y^'+(3y)/x =(y^2)/x ?

The solution for -y^'+(3y)/x =(y^2)/x is y=-(3e^{3c_{1}}x^3)/(1-e^{3c_{1)}x^3}

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-y^'+(3y)/x =(y^2)/x

- y^{^{'}} + \frac{3 y}{x} = \frac{y ^{2}}{x}

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

Solution steps

- y^{'} (x) + \frac{3 y}{x} = \frac{y ^{2}}{x}

Solve separable ODE:

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

What is the solution for -y^'+(3y)/x =(y^2)/x ?
The solution for -y^'+(3y)/x =(y^2)/x is y=-(3e^{3c_{1}}x^3)/(1-e^{3c_{1)}x^3}