What is inverse oflaplace (-2)/(s+3) ?

The answer to inverse oflaplace (-2)/(s+3) is -2e^{-3t}

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inverse oflaplace (-2)/(s+3)

inverse laplace

\frac{- 2}{s + 3}

- 2 e^{- 3 t}

Solution steps

L^{- 1} {\frac{- 2}{s + 3}}

= L^{- 1} {- 2 \cdot \frac{1}{s + 3}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - 2 L^{- 1} {\frac{1}{s + 3}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 3}} = e^{- 3 t}

= - 2 e^{- 3 t}

What is inverse oflaplace (-2)/(s+3) ?
The answer to inverse oflaplace (-2)/(s+3) is -2e^{-3t}