What is the solution for y^'=(x+1)/y ?

The solution for y^'=(x+1)/y is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}

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y^'=(x+1)/y

y^{^{'}} = \frac{x + 1}{y}

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

Solution steps

y^{'} (x) = \frac{x + 1}{y}

Solve separable ODE:

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

What is the solution for y^'=(x+1)/y ?
The solution for y^'=(x+1)/y is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}