What is the derivative of 4x^3-5x^2+4x-1 ?

The derivative of 4x^3-5x^2+4x-1 is 12x^2-10x+4

What is the first derivative of 4x^3-5x^2+4x-1 ?

The first derivative of 4x^3-5x^2+4x-1 is 12x^2-10x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (4 x^{3} - 5 x^{2} + 4 x - 1)

12 x^{2} - 10 x + 4

Solution steps

\frac{d}{d x} (4 x^{3} - 5 x^{2} + 4 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 12 x^{2} - 10 x + 4 - 0

Simplify

= 12 x^{2} - 10 x + 4

What is the derivative of 4x^3-5x^2+4x-1 ?
The derivative of 4x^3-5x^2+4x-1 is 12x^2-10x+4
What is the first derivative of 4x^3-5x^2+4x-1 ?
The first derivative of 4x^3-5x^2+4x-1 is 12x^2-10x+4