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Popular Calculus >

integral from 1 to 2 of 3-6/(x^2)

Solution

\int_{1}^{2} 3 - \frac{6}{x ^{2}} d x

Solution

0

Solution steps

\int_{1}^{2} 3 - \frac{6}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 d x - \int_{1}^{2} \frac{6}{x ^{2}} d x

\int_{1}^{2} 3 d x = 3

\int_{1}^{2} \frac{6}{x ^{2}} d x = 3

= 3 - 3

Simplify

= 0

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of 3-6/(x^2) ?
The integral from 1 to 2 of 3-6/(x^2) is 0