What is the solution for y^{''}+12y^'+36y=0,y(1)=0,y^'(1)=1 ?

The solution for y^{''}+12y^'+36y=0,y(1)=0,y^'(1)=1 is y=-e^{6-6t}+e^{6-6t}t

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y^{''}+12y^'+36y=0,y(1)=0,y^'(1)=1

y^{^{''}} + 12 y^{^{'}} + 36 y = 0, y (1) = 0, y^{^{'}} (1) = 1

y = - e^{6 - 6 t} + e^{6 - 6 t} t

Solution steps

y^{''} (t) + 12 y^{'} (t) + 36 y = 0

Solve linear ODE:

y = - e^{6 - 6 t} + e^{6 - 6 t} t

y = - e^{6 - 6 t} + e^{6 - 6 t} t

What is the solution for y^{''}+12y^'+36y=0,y(1)=0,y^'(1)=1 ?
The solution for y^{''}+12y^'+36y=0,y(1)=0,y^'(1)=1 is y=-e^{6-6t}+e^{6-6t}t