What is the tangent of e^{-3t},\at t=0 ?

The tangent of e^{-3t},\at t=0 is y=-3t+1

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tangent of e^{-3t},\at t=0

tangent of

e^{- 3 t}, at t = 0

y = - 3 t + 1

Solution steps

Find the tangent point:

(0, 1)

Find the slope of

y = e^{- 3 t} : \frac{d y}{d t} = - 3 e^{- 3 t}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 3

Find the line with slope m=

- 3

and passing through

(0, 1) : y = - 3 t + 1

y = - 3 t + 1

What is the tangent of e^{-3t},\at t=0 ?
The tangent of e^{-3t},\at t=0 is y=-3t+1