What is the tangent of f(x)=x^2+x,\at x=-4 ?

The tangent of f(x)=x^2+x,\at x=-4 is y=-7x-16

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tangent of f(x)=x^2+x,\at x=-4

tangent of

f (x) = x^{2} + x, at x = - 4

y = - 7 x - 16

Solution steps

Find the tangent point:

(- 4, 12)

Find the slope of

f (x) = x^{2} + x : \frac{df ( x )}{d x} = 2 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 7

Find the line with slope m=

- 7

and passing through

(- 4, 12) : y = - 7 x - 16

y = - 7 x - 16

What is the tangent of f(x)=x^2+x,\at x=-4 ?
The tangent of f(x)=x^2+x,\at x=-4 is y=-7x-16