What is the derivative of 1-x/2+(x^2/9) ?

The derivative of 1-x/2+(x^2/9) is (2x)/9-1/2

What is the first derivative of 1-x/2+(x^2/9) ?

The first derivative of 1-x/2+(x^2/9) is (2x)/9-1/2

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\frac{d}{d x} (1 - \frac{x}{2} + \frac{x ^{2}}{9})

\frac{2 x}{9} - \frac{1}{2}

Solution steps

\frac{d}{d x} (1 - \frac{x}{2} + \frac{x ^{2}}{9})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{x}{2}) + \frac{d}{d x} (\frac{x ^{2}}{9})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{x}{2}) = \frac{1}{2}

\frac{d}{d x} (\frac{x ^{2}}{9}) = \frac{2 x}{9}

= 0 - \frac{1}{2} + \frac{2 x}{9}

Simplify

= \frac{2 x}{9} - \frac{1}{2}

What is the derivative of 1-x/2+(x^2/9) ?
The derivative of 1-x/2+(x^2/9) is (2x)/9-1/2
What is the first derivative of 1-x/2+(x^2/9) ?
The first derivative of 1-x/2+(x^2/9) is (2x)/9-1/2