What is the tangent of h(x)= 1/(x-2),(3,1) ?

The tangent of h(x)= 1/(x-2),(3,1) is y=-x+4

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tangent of h(x)= 1/(x-2),(3,1)

tangent of

h (x) = \frac{1}{x - 2}, (3, 1)

y = - x + 4

Solution steps

Find the slope of

h (x) = \frac{1}{x - 2} : \frac{d h ( x )}{d x} = - \frac{1}{( x - 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(3, 1) : y = - x + 4

y = - x + 4

What is the tangent of h(x)= 1/(x-2),(3,1) ?
The tangent of h(x)= 1/(x-2),(3,1) is y=-x+4