What is the solution for y^'+3.25y=26 ?

The solution for y^'+3.25y=26 is y=-(e^{-3.25t-c_{1}})/(3.25)+(26)/(3.25)

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y^'+3.25y=26

y^{^{'}} + 3.25 y = 26

y = - \frac{e ^{- 3.25 t - c_{1}}}{3.25} + \frac{26}{3.25}

Solution steps

y^{'} (t) + 3.25 y = 26

Solve separable ODE:

y = - \frac{e ^{- 3.25 t - c_{1}}}{3.25} + \frac{26}{3.25}

y = - \frac{e ^{- 3.25 t - c_{1}}}{3.25} + \frac{26}{3.25}

What is the solution for y^'+3.25y=26 ?
The solution for y^'+3.25y=26 is y=-(e^{-3.25t-c_{1}})/(3.25)+(26)/(3.25)