What is area f(x)=-x^2+4,y+2x-4=0 ?

The answer to area f(x)=-x^2+4,y+2x-4=0 is 4/3

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area f(x)=-x^2+4,y+2x-4=0

area

f (x) = - x^{2} + 4, y + 2 x - 4 = 0

\frac{4}{3}

Decimal

1.33333 \dots

Solution steps

Isolate

y

for

y + 2 x - 4 = 0 : y = - 2 x + 4

Apply the area formula:

\int_{0}^{2} - 2 x + 4 - (- x^{2} + 4) d x

Solve

\int_{0}^{2} - 2 x + 4 - (- x^{2} + 4) d x : \frac{4}{3}

The area is:

= \frac{4}{3}

What is area f(x)=-x^2+4,y+2x-4=0 ?
The answer to area f(x)=-x^2+4,y+2x-4=0 is 4/3