derivative of sin(2x-2pi)

解答

\frac{d}{d x} (sin (2 x - 2 π))

cos (2 x) \cdot 2

求解步骤

\frac{d}{d x} (sin (2 x - 2 π))

化简

sin (2 x - 2 π) : sin (2 x)

= \frac{d}{d x} (sin (2 x))

使用连锁律:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= cos (2 x) \cdot 2

\int \frac{1}{x ^{2} + 2 x + 5} d x

\frac{\partial}{\partial x} (ln (x^{6} + 1) + y^{2})

\frac{d}{d x} (\frac{5}{12} (3 + 5) x^{3})

x \to - \infty lim (x^{0})

\frac{\partial}{\partial x} (e^{y} - x e^{x})