What is the derivative of 5/(3x-4) ?

The derivative of 5/(3x-4) is -(15)/((3x-4)^2)

What is the first derivative of 5/(3x-4) ?

The first derivative of 5/(3x-4) is -(15)/((3x-4)^2)

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\frac{d}{d x} (\frac{5}{3 x - 4})

- \frac{15}{( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{3 x - 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{3 x - 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((3 x - 4)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 x - 4 ) ^{2}} \frac{d}{d x} (3 x - 4)

= - \frac{1}{( 3 x - 4 ) ^{2}} \frac{d}{d x} (3 x - 4)

\frac{d}{d x} (3 x - 4) = 3

= 5 (- \frac{1}{( 3 x - 4 ) ^{2}} \cdot 3)

Simplify

5 (- \frac{1}{( 3 x - 4 ) ^{2}} \cdot 3) : - \frac{15}{( 3 x - 4 ) ^{2}}

= - \frac{15}{( 3 x - 4 ) ^{2}}

What is the derivative of 5/(3x-4) ?
The derivative of 5/(3x-4) is -(15)/((3x-4)^2)
What is the first derivative of 5/(3x-4) ?
The first derivative of 5/(3x-4) is -(15)/((3x-4)^2)