What is the derivative of 2t^2-3t-1 ?

The derivative of 2t^2-3t-1 is 4t-3

What is the first derivative of 2t^2-3t-1 ?

The first derivative of 2t^2-3t-1 is 4t-3

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derivative of

2 t^{2} - 3 t - 1

4 t - 3

Solution steps

\frac{d}{d t} (2 t^{2} - 3 t - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 t^{2}) - \frac{d}{d t} (3 t) - \frac{d}{d t} (1)

\frac{d}{d t} (2 t^{2}) = 4 t

\frac{d}{d t} (3 t) = 3

\frac{d}{d t} (1) = 0

= 4 t - 3 - 0

Simplify

= 4 t - 3

What is the derivative of 2t^2-3t-1 ?
The derivative of 2t^2-3t-1 is 4t-3
What is the first derivative of 2t^2-3t-1 ?
The first derivative of 2t^2-3t-1 is 4t-3