What is the tangent of y= 1/(sqrt(x)),(4, 1/2) ?

The tangent of y= 1/(sqrt(x)),(4, 1/2) is y=-1/16 x+3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y= 1/(sqrt(x)),(4, 1/2)

tangent of

y = \frac{1}{x}, (4, \frac{1}{2})

y = - \frac{1}{16} x + \frac{3}{4}

Solution steps

Find the slope of

y = \frac{1}{x} : \frac{d y}{d x} = - \frac{1}{2 x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{16}

Find the line with slope m=

- \frac{1}{16}

and passing through

(4, \frac{1}{2}) : y = - \frac{1}{16} x + \frac{3}{4}

y = - \frac{1}{16} x + \frac{3}{4}

What is the tangent of y= 1/(sqrt(x)),(4, 1/2) ?
The tangent of y= 1/(sqrt(x)),(4, 1/2) is y=-1/16 x+3/4