What is the tangent of y=(2x)/((x+1)^2),(0,0) ?

The tangent of y=(2x)/((x+1)^2),(0,0) is y=2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=(2x)/((x+1)^2),(0,0)

tangent of

y = \frac{2 x}{( x + 1 ) ^{2}}, (0, 0)

y = 2 x

Solution steps

Find the slope of

y = \frac{2 x}{( x + 1 ) ^{2}} : \frac{d y}{d x} = \frac{2 ( 1 - x )}{( x + 1 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(0, 0) : y = 2 x

y = 2 x

What is the tangent of y=(2x)/((x+1)^2),(0,0) ?
The tangent of y=(2x)/((x+1)^2),(0,0) is y=2x