What is the solution for 2ycos(x)dx+3sin(x)dy=0 ?

The solution for 2ycos(x)dx+3sin(x)dy=0 is y=(c_{1})/(sin^{2/3)(x)}

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2ycos(x)dx+3sin(x)dy=0

2 y cos (x) d x + 3 sin (x) d y = 0

y = \frac{c _{1}}{sin ^{\frac{2}{3}} ( x )}

Solution steps

2 y cos (x) d x + 3 sin (x) d y = 0

Solve separable ODE:

y = \frac{c _{1}}{sin ^{\frac{2}{3}} ( x )}

y = \frac{c _{1}}{sin ^{\frac{2}{3}} ( x )}

What is the solution for 2ycos(x)dx+3sin(x)dy=0 ?
The solution for 2ycos(x)dx+3sin(x)dy=0 is y=(c_{1})/(sin^{2/3)(x)}