What is the derivative of-4e^x-sin(x-9) ?

The derivative of-4e^x-sin(x-9) is -4e^x-cos(x)

What is the first derivative of-4e^x-sin(x-9) ?

The first derivative of-4e^x-sin(x-9) is -4e^x-cos(x)

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\frac{d}{d x} (- 4 e^{x} - sin (x) - 9)

- 4 e^{x} - cos (x)

Solution steps

\frac{d}{d x} (- 4 e^{x} - sin (x) - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 e^{x}) - \frac{d}{d x} (sin (x)) - \frac{d}{d x} (9)

\frac{d}{d x} (4 e^{x}) = 4 e^{x}

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (9) = 0

= - 4 e^{x} - cos (x) - 0

Simplify

= - 4 e^{x} - cos (x)

What is the derivative of-4e^x-sin(x-9) ?
The derivative of-4e^x-sin(x-9) is -4e^x-cos(x)
What is the first derivative of-4e^x-sin(x-9) ?
The first derivative of-4e^x-sin(x-9) is -4e^x-cos(x)