What is (\partial)/(\partial y)(y-cos(y)) ?

The answer to (\partial)/(\partial y)(y-cos(y)) is 1+sin(y)

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(\partial)/(\partial y)(y-cos(y))

\frac{\partial}{\partial y} (y - cos (y))

1 + sin (y)

Solution steps

\frac{\partial}{\partial y} (y - cos (y))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (cos (y))

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= 1 - (- sin (y))

Simplify

= 1 + sin (y)

What is (\partial)/(\partial y)(y-cos(y)) ?
The answer to (\partial)/(\partial y)(y-cos(y)) is 1+sin(y)