What is the derivative of sin(x^3-3x) ?

The derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)

What is the first derivative of sin(x^3-3x) ?

The first derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)

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\frac{d}{d x} (sin (x^{3} - 3 x))

cos (x^{3} - 3 x) (3 x^{2} - 3)

Solution steps

\frac{d}{d x} (sin (x^{3} - 3 x))

Apply the chain rule:

cos (x^{3} - 3 x) \frac{d}{d x} (x^{3} - 3 x)

= cos (x^{3} - 3 x) \frac{d}{d x} (x^{3} - 3 x)

\frac{d}{d x} (x^{3} - 3 x) = 3 x^{2} - 3

= cos (x^{3} - 3 x) (3 x^{2} - 3)

What is the derivative of sin(x^3-3x) ?
The derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)
What is the first derivative of sin(x^3-3x) ?
The first derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)