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Popular Calculus >

x^2y^'=y^2+3xy

Solution

x^{2} y^{^{'}} = y^{2} + 3 x y

Solution

y = \frac{2 x ^{3}}{- x ^{2} + c _{1}}

Solution steps

x^{2} y^{'} (x) = y^{2} + 3 x y

Solve Bernoulli ODE:

y = \frac{2 x ^{3}}{- x ^{2} + c _{1}}

y = \frac{2 x ^{3}}{- x ^{2} + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for x^2y^'=y^2+3xy ?
The solution for x^2y^'=y^2+3xy is y=(2x^3)/(-x^2+c_{1)}