What is the tangent of f(x)=12sqrt(x)-2x,\at x=9 ?

The tangent of f(x)=12sqrt(x)-2x,\at x=9 is y=18

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tangent of f(x)=12sqrt(x)-2x,\at x=9

tangent of

f (x) = 12 x - 2 x, at x = 9

y = 18

Solution steps

Find the tangent point:

(9, 18)

Find the slope of

f (x) = 12 x - 2 x : \frac{df ( x )}{d x} = \frac{6}{x} - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(9, 18) : y = 18

y = 18

What is the tangent of f(x)=12sqrt(x)-2x,\at x=9 ?
The tangent of f(x)=12sqrt(x)-2x,\at x=9 is y=18