What is the tangent of y=x^3-2x^2+5,\at x=2 ?

The tangent of y=x^3-2x^2+5,\at x=2 is y=4x-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=x^3-2x^2+5,\at x=2

tangent of

y = x^{3} - 2 x^{2} + 5, at x = 2

y = 4 x - 3

Solution steps

Find the tangent point:

(2, 5)

Find the slope of

y = x^{3} - 2 x^{2} + 5 : \frac{d y}{d x} = 3 x^{2} - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(2, 5) : y = 4 x - 3

y = 4 x - 3

What is the tangent of y=x^3-2x^2+5,\at x=2 ?
The tangent of y=x^3-2x^2+5,\at x=2 is y=4x-3