What is the tangent of x^3-6x^2-34x+40,\at x=4 ?

The tangent of x^3-6x^2-34x+40,\at x=4 is y=-34x+8

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tangent of x^3-6x^2-34x+40,\at x=4

tangent of

x^{3} - 6 x^{2} - 34 x + 40, at x = 4

y = - 34 x + 8

Solution steps

Find the tangent point:

(4, - 128)

Find the slope of

y = x^{3} - 6 x^{2} - 34 x + 40 : \frac{d y}{d x} = 3 x^{2} - 12 x - 34

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 34

Find the line with slope m=

- 34

and passing through

(4, - 128) : y = - 34 x + 8

y = - 34 x + 8

What is the tangent of x^3-6x^2-34x+40,\at x=4 ?
The tangent of x^3-6x^2-34x+40,\at x=4 is y=-34x+8