What is the derivative of 2(3x^2+x-3^2) ?

The derivative of 2(3x^2+x-3^2) is 4(3x^2+x-3)(6x+1)

What is the first derivative of 2(3x^2+x-3^2) ?

The first derivative of 2(3x^2+x-3^2) is 4(3x^2+x-3)(6x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (2 (3 x^{2} + x - 3)^{2})

4 (3 x^{2} + x - 3) (6 x + 1)

Solution steps

\frac{d}{d x} (2 (3 x^{2} + x - 3)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((3 x^{2} + x - 3)^{2})

Apply the chain rule:

2 (3 x^{2} + x - 3) \frac{d}{d x} (3 x^{2} + x - 3)

= 2 (3 x^{2} + x - 3) \frac{d}{d x} (3 x^{2} + x - 3)

\frac{d}{d x} (3 x^{2} + x - 3) = 6 x + 1

= 2 \cdot 2 (3 x^{2} + x - 3) (6 x + 1)

Simplify

= 4 (3 x^{2} + x - 3) (6 x + 1)

What is the derivative of 2(3x^2+x-3^2) ?
The derivative of 2(3x^2+x-3^2) is 4(3x^2+x-3)(6x+1)
What is the first derivative of 2(3x^2+x-3^2) ?
The first derivative of 2(3x^2+x-3^2) is 4(3x^2+x-3)(6x+1)