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Popular Calculus >

integral from 1 to 4 of (x^2-3x)

Solution

\int_{1}^{4} (x^{2} - 3 x) d x

Solution

- \frac{3}{2}

+1

Decimal

- 1.5

Solution steps

\int_{1}^{4} x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x - \int_{1}^{4} 3 x d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 3 x d x = \frac{45}{2}

= 21 - \frac{45}{2}

Simplify

21 - \frac{45}{2} : - \frac{3}{2}

= - \frac{3}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (x^2-3x) ?
The integral from 1 to 4 of (x^2-3x) is -3/2