What is the limit as x approaches 0 of (1-6x)^{2/x} ?

The limit as x approaches 0 of (1-6x)^{2/x} is 1/(e^{12)}

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limit as x approaches 0 of (1-6x)^{2/x}

x \to 0 lim ((1 - 6 x)^{\frac{2}{x}})

\frac{1}{e ^{12}}

Decimal

6.14421 E - 6

Solution steps

x \to 0 lim ((1 - 6 x)^{\frac{2}{x}})

Apply exponent rules

= x \to 0 lim (e^{\frac{2}{x} l n (1 - 6 x)})

Apply the Limit Chain Rule:

\frac{1}{e ^{12}}

= \frac{1}{e ^{12}}

What is the limit as x approaches 0 of (1-6x)^{2/x} ?
The limit as x approaches 0 of (1-6x)^{2/x} is 1/(e^{12)}