What is the tangent of-3x^2+2xy+2y^3=125,(3,4) ?

The tangent of-3x^2+2xy+2y^3=125,(3,4) is y= 5/51 x+63/17

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tangent of-3x^2+2xy+2y^3=125,(3,4)

tangent of

- 3 x^{2} + 2 x y + 2 y^{3} = 125, (3, 4)

y = \frac{5}{51} x + \frac{63}{17}

Solution steps

Find the slope of

- 3 x^{2} + 2 x y + 2 y^{3} = 125 : \frac{d y}{d x} = \frac{3 x - y}{x + 3 y ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{51}

Find the line with slope m=

\frac{5}{51}

and passing through

(3, 4) : y = \frac{5}{51} x + \frac{63}{17}

y = \frac{5}{51} x + \frac{63}{17}

What is the tangent of-3x^2+2xy+2y^3=125,(3,4) ?
The tangent of-3x^2+2xy+2y^3=125,(3,4) is y= 5/51 x+63/17