What is the derivative of 3x^3-3x^2-3x+2 ?

The derivative of 3x^3-3x^2-3x+2 is 9x^2-6x-3

What is the first derivative of 3x^3-3x^2-3x+2 ?

The first derivative of 3x^3-3x^2-3x+2 is 9x^2-6x-3

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\frac{d}{d x} (3 x^{3} - 3 x^{2} - 3 x + 2)

9 x^{2} - 6 x - 3

Solution steps

\frac{d}{d x} (3 x^{3} - 3 x^{2} - 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 9 x^{2} - 6 x - 3 + 0

Simplify

= 9 x^{2} - 6 x - 3

What is the derivative of 3x^3-3x^2-3x+2 ?
The derivative of 3x^3-3x^2-3x+2 is 9x^2-6x-3
What is the first derivative of 3x^3-3x^2-3x+2 ?
The first derivative of 3x^3-3x^2-3x+2 is 9x^2-6x-3