What is the tangent of f(x)=x^2-8,(4,8) ?

The tangent of f(x)=x^2-8,(4,8) is y=8x-24

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tangent of f(x)=x^2-8,(4,8)

tangent of

f (x) = x^{2} - 8, (4, 8)

y = 8 x - 24

Solution steps

Find the slope of

f (x) = x^{2} - 8 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(4, 8) : y = 8 x - 24

y = 8 x - 24

What is the tangent of f(x)=x^2-8,(4,8) ?
The tangent of f(x)=x^2-8,(4,8) is y=8x-24