What is the tangent of y=7ln((e^x+e^{-x})/2),(0,0) ?

The tangent of y=7ln((e^x+e^{-x})/2),(0,0) is y=0

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tangent of y=7ln((e^x+e^{-x})/2),(0,0)

tangent of

y = 7 ln (\frac{e ^{x} + e ^{- x}}{2}), (0, 0)

y = 0

Solution steps

Find the slope of

y = 7 ln (\frac{e ^{x} + e ^{- x}}{2}) : \frac{d y}{d x} = \frac{7 ( e ^{2 x} - 1 )}{e ^{2 x} + 1}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(0, 0) : y = 0

y = 0

What is the tangent of y=7ln((e^x+e^{-x})/2),(0,0) ?
The tangent of y=7ln((e^x+e^{-x})/2),(0,0) is y=0