What is the tangent of f(x)=x^2-1,(-1,0) ?

The tangent of f(x)=x^2-1,(-1,0) is y=-2x-2

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tangent of f(x)=x^2-1,(-1,0)

tangent of

f (x) = x^{2} - 1, (- 1, 0)

y = - 2 x - 2

Solution steps

Find the slope of

f (x) = x^{2} - 1 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(- 1, 0) : y = - 2 x - 2

y = - 2 x - 2

What is the tangent of f(x)=x^2-1,(-1,0) ?
The tangent of f(x)=x^2-1,(-1,0) is y=-2x-2