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Popular Calculus >

y^'=1+y^2+x+xy^2

Solution

y^{^{'}} = 1 + y^{2} + x + x y^{2}

Solution

y = tan (x + \frac{x ^{2}}{2} + c_{1})

Solution steps

y^{'} (x) = 1 + y^{2} + x + x y^{2}

Solve separable ODE:

y = tan (x + \frac{x ^{2}}{2} + c_{1})

y = tan (x + \frac{x ^{2}}{2} + c_{1})

Graph

Popular Examples

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Frequently Asked Questions (FAQ)

What is the solution for y^'=1+y^2+x+xy^2 ?
The solution for y^'=1+y^2+x+xy^2 is y=tan(x+(x^2)/2+c_{1})