What is the integral of sin(5x-1) ?

The integral of sin(5x-1) is -1/5 cos(5x-1)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of sin(5x-1)

\int sin (5 x - 1) d x

- \frac{1}{5} cos (5 x - 1) + C

Solution steps

\int sin (5 x - 1) d x

Apply u-substitution

= \int sin (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{5} (- cos (u))

Substitute back

u = 5 x - 1

= \frac{1}{5} (- cos (5 x - 1))

Simplify

= - \frac{1}{5} cos (5 x - 1)

Add a constant to the solution

= - \frac{1}{5} cos (5 x - 1) + C

What is the integral of sin(5x-1) ?
The integral of sin(5x-1) is -1/5 cos(5x-1)+C