What is the slope of y=(16)/((x+4)^2),(0,1) ?

The slope of y=(16)/((x+4)^2),(0,1) is -1/2

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slope of y=(16)/((x+4)^2),(0,1)

slope

y = \frac{16}{( x + 4 ) ^{2}}, (0, 1)

- \frac{1}{2}

Decimal

- 0.5

Solution steps

y = \frac{16}{( x + 4 ) ^{2}}

In order to find the slope of the function, take the derivative of

\frac{16}{( x + 4 ) ^{2}}

\frac{d}{d x} (\frac{16}{( x + 4 ) ^{2}}) = - \frac{32}{( x + 4 ) ^{3}}

- \frac{32}{( x + 4 ) ^{3}}

Find the value of

- \frac{32}{( x + 4 ) ^{3}}

for

x = 0 : - \frac{1}{2}

- \frac{1}{2}

What is the slope of y=(16)/((x+4)^2),(0,1) ?
The slope of y=(16)/((x+4)^2),(0,1) is -1/2