What is (\partial)/(\partial x)(-2xy(6-x-y)) ?

The answer to (\partial)/(\partial x)(-2xy(6-x-y)) is -2y(-2x-y+6)

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(\partial)/(\partial x)(-2xy(6-x-y))

\frac{\partial}{\partial x} (- 2 x y (6 - x - y))

- 2 y (- 2 x - y + 6)

Solution steps

\frac{\partial}{\partial x} (- 2 x y (6 - x - y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 y \frac{\partial}{\partial x} (x (6 - x - y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 6 - x - y

= - 2 y (\frac{\partial}{\partial x} (x) (6 - x - y) + \frac{\partial}{\partial x} (6 - x - y) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (6 - x - y) = - 1

= - 2 y (1 \cdot (6 - x - y) + (- 1) x)

Simplify

- 2 y (1 \cdot (6 - x - y) + (- 1) x) : - 2 y (- 2 x - y + 6)

= - 2 y (- 2 x - y + 6)

What is (\partial)/(\partial x)(-2xy(6-x-y)) ?
The answer to (\partial)/(\partial x)(-2xy(6-x-y)) is -2y(-2x-y+6)