What is the tangent of f(x)= 2/(sqrt(x)),\at 1/16 ?

The tangent of f(x)= 2/(sqrt(x)),\at 1/16 is y=-1/(a_{0)^{3/2}}x+3/(sqrt(a_{0))}

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tangent of f(x)= 2/(sqrt(x)),\at 1/16

tangent of

f (x) = \frac{2}{x}, at \frac{1}{16}

y = - \frac{1}{a _{0}^{\frac{3}{2}}} x + \frac{3}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0}})

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{1}{x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{a _{0}^{\frac{3}{2}}}

Find the line with slope m=

- \frac{1}{a _{0}^{\frac{3}{2}}}

and passing through

(a_{0}, \frac{2}{a _{0}}) : y = - \frac{1}{a _{0}^{\frac{3}{2}}} x + \frac{3}{a _{0}}

y = - \frac{1}{a _{0}^{\frac{3}{2}}} x + \frac{3}{a _{0}}

What is the tangent of f(x)= 2/(sqrt(x)),\at 1/16 ?
The tangent of f(x)= 2/(sqrt(x)),\at 1/16 is y=-1/(a_{0)^{3/2}}x+3/(sqrt(a_{0))}